This is an extraneous solution. It looks like you solved the equation Â correctly, but you forgot to evaluate both values for x in the original equation. It is a Quadratic Equation!

Just repeat the process for each one. While no mistake was made solving the equation, we found a solution that does not satisfy the original equation. When you square both sides and then solve the resulting equation, , you do get x = 0 as a possible solution. { bidder: 'triplelift', params: { inventoryCode: 'Cambridge_HDX' }}, Check your answer. {code: 'ad_contentslot_1', pubstack: { adUnitName: 'cdo_mpuslot', adUnitPath: '/2863368/mpuslot' }, mediaTypes: { banner: { sizes: [[300, 250], [336, 280]] } }, { bidder: 'triplelift', params: { inventoryCode: 'Cambridge_MidArticle' }}, googletag.pubads().setTargeting("cdo_tc", "resp"); { bidder: 'sovrn', params: { tagid: '387233' }},

'max': 30, { bidder: 'pubmatic', params: { publisherId: '158679', adSlot: 'cdo_mpuslot2' }}]}]; addPrebidAdUnits(pbAdUnits); Remember to square both sides: , which becomes . Remember to include the entire binomial when you square both sides; then solve for. bids: [{ bidder: 'rubicon', params: { accountId: '17282', siteId: '162036', zoneId: '776140', position: 'atf' }}, { bidder: 'appnexus', params: { placementId: '11654157' }},

{ bidder: 'triplelift', params: { inventoryCode: 'Cambridge_SR' }}, These solutions are called extraneous solutions. 'cap': true 4. }], It looks like you only squared the left side of the equation.

googletag.cmd.push(function() { $$\sqrt 1 + 1 = 0$$ { bidder: 'ix', params: { siteId: '195453', size: [300, 50] }},

We have now successfully removed both square roots.

$$2 = 0,NOTOK$$. Raise both sides of the equation to the index of the radical; in this case, cube both sides. It is important to isolate a radical on one side of the equation and simplify as much as possible before squaring. userIds: [{ However, x = 0 is an extraneous solution since it does not make the original equation true! { bidder: 'sovrn', params: { tagid: '448834' }}, name: "pbjs-unifiedid", Example 1: Solve the radical equation The radical is by itself on one side so it is fine to square both sides of the equations to get rid of the radical symbol. 'max': 3, { bidder: 'appnexus', params: { placementId: '11654150' }}, { bidder: 'criteo', params: { networkId: 7100, publisherSubId: 'cdo_mpuslot' }}, priceGranularity: customGranularity, dfpSlots['leftslot'] = googletag.defineSlot('/2863368/leftslot', [[120, 600], [160, 600]], 'ad_leftslot').defineSizeMapping(mapping_leftslot).setTargeting('sri', '0').setTargeting('vp', 'top').setTargeting('hp', 'left').addService(googletag.pubads()); 'min': 8.50, { bidder: 'sovrn', params: { tagid: '387233' }}, More examples on how to Divide Radical Expressions. And when the instructions for an exercise say to check one's answers, this means that you need to show your check as part of your hand-in work..

{ bidder: 'appnexus', params: { placementId: '11654149' }}, var pbTabletSlots = [ bids: [{ bidder: 'rubicon', params: { accountId: '17282', siteId: '162036', zoneId: '776142', position: 'btf' }},

Now check both solutions by substituting them into the original equation. The graphs of Â and Â are plotted below. Notice how the radical contains a binomial: x + 8. The correct answer is x = 10.

googletag.pubads().setTargeting("cdo_ptl", "ex-mcp"); $${x_1} = 0$$ $$\sqrt 4 - \sqrt 1 = 1$$

$${(\sqrt {3x + 4} )^2} = {(1 + \sqrt {2x + 1} )^2}$$

Confirm solutions by substituting them into the original equation. bids: [{ bidder: 'rubicon', params: { accountId: '17282', siteId: '162036', zoneId: '776156', position: 'atf' }}, { bidder: 'triplelift', params: { inventoryCode: 'Cambridge_MidArticle' }}, { bidder: 'onemobile', params: { dcn: '8a969411017171829a5c82bb4deb000b', pos: 'cdo_rightslot_flex' }}, The proposed solutions are $x=3$ and $x=83$. { bidder: 'ix', params: { siteId: '195465', size: [300, 250] }}, {code: 'ad_contentslot_1', pubstack: { adUnitName: 'cdo_mpuslot', adUnitPath: '/2863368/mpuslot' }, mediaTypes: { banner: { sizes: [[300, 250], [336, 280]] } }, { bidder: 'ix', params: { siteId: '195453', size: [300, 250] }}, if(!isPlusPopupShown()) {code: 'ad_rightslot', pubstack: { adUnitName: 'cdo_rightslot', adUnitPath: '/2863368/rightslot' }, mediaTypes: { banner: { sizes: [[300, 250]] } }, Are you sure you want to remove #bookConfirmation# { Remember to square both sides: , which becomes . Incorrect. Here is a list of topics: 1. $$4x - 3 - 1 + 4x - 4{x^2} = 0$$ initAdSlotRefresher(); iasLog("exclusion label : resp");

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